4 Sep
2006
4 Sep
'06
3:11 a.m.
David Ellerman begins,
When a Boolean algebra B is treated as a Boolean ring in the usual ...
Boolean algebras actually have the additional surprise that, because their multiplication (meet) is idempotent (as well as commutative and associative), it distributes over itself ( a(bc) = (ab)(ac) ) so that one can use multiplication as a third addition candidate (the first two having been the more usual symmetric difference and join, of course). Cheers, and Happy Labor Day (in the US, anyway), -- Fred