16 Sep
2010
16 Sep
'10
8:32 a.m.
Hi, Peter, You're right -- I *had* lost it:
z(t) = sin 3t
Oops, this should have been z(t) = sin 6t (in my parametrization and yours), or else it won't plot correctly in 3 dimensions.
Mmm ... I think "3t" remains correct in mine ... or have I lost it?
Not sure. Your parametrization of the (x,y)-coordinates is periodic with period pi. Your parameterization of z is periodic with period 2/3 pi. This seems to imply that for t in [0,pi], your curve traces out the same (x,y) coordinates as for [pi,2pi], but with the z coordinate negated.
Right, 6t it should have been, all along. Sorry 'bout that :-) . Cheers, -- Fred