29 Apr
2003
29 Apr
'03
2:12 a.m.
Vaughan has noticed that I hadn't broken the commutative habit. So let me start again. He asked if one can determine a minimal equational theory with the theory of distributive lattices as its unique maximal consistent extension. Yes, here's an example: x meet 1 = x, x meet 0 = 0, 1 join 1 = 1, 1 join 0 = 1, 0 join 1 = 1, 0 join 0 = 0. (I was missing the penultimate equation.) There is a Klein-group's worth of variations. One operation simultaneously interchanges meet and join, 0 and 1. Another operation simultaneously interchanges the arguments of the operators. I'll hazard that the resulting four theories are the only ones that do the trick.
8434
Age (days ago)
8434
Last active (days ago)
0 comments
1 participants
participants (1)
-
Peter Freyd