charact. of absolute equalisers
Dear categorists, I wonder whether the following result is known: Call an equaliser in a category C *absolute* if it is preserved by all functors. Proposition: An equaliser e:A->B, u,v:B->C is absolute if and only if there are maps p:B->A, h1,h2,...hn:C->B such that pe=id, ep=h1 u h1 u = h2 v h2 u = h3 v ... hn v = id Proof: An equaliser endowed with such maps is obviously preserved by any functor since whenever we have maps e,u,v,p,h1...hn such that ue=ve together with the equations listed above then e equalises u and v. For the converse consider the functor which maps X to C(B,X)/~ where ~ is the left congruence generated by u~v, i.e., f~g iff there are h1...hn such that f=h1 u h1 v = h2 u ... hn v = g If this functor preserves the equaliser then, since Fu([id]) = Fv([id]) we obtain p:B->A such that ep~id. Thus we have maps h1..hn with the desired properties. To show pe=id we calculate as follows: epe=h1 u e = h1 v e = h2 u e = ... = hn v e = e, so pe=id since e is a mono. Best wishes, Martin Hofmann
Bob Pare characterized absolute coequalizers in exactly those terms (dualized, of course) in his 1969 dissertation under Lambek.
Dear Martin, These were studied in my PhD thesis "Absoluteness Properties in Category Theory" McGill 1969. See "Absolute Coequalizers" Springer Lecture Notes 86 (1969), 132-145, and "On Absolute Colimits" J. Alg. 19 (1971) 80-95. The proof I give shows that for colimits it is sufficient to test preservation by the Yoneda functor (or all representables). So while the Yoneda embedding preserves all limits, it preserves no colimits execpt those it absolutely has to. It's interesting that you came up with the same name for them. Bob
Dear categorists,
I wonder whether the following result is known:
Call an equaliser in a category C *absolute* if it is preserved by all functors.
Proposition: An equaliser e:A->B, u,v:B->C is absolute if and only if there are maps p:B->A, h1,h2,...hn:C->B such that
pe=id, ep=h1 u h1 u = h2 v h2 u = h3 v ... hn v = id
Proof: An equaliser endowed with such maps is obviously preserved by any functor since whenever we have maps e,u,v,p,h1...hn such that ue=ve together with the equations listed above then e equalises u and v.
For the converse consider the functor which maps X to C(B,X)/~ where ~ is the left congruence generated by u~v, i.e., f~g iff there are h1...hn such that f=h1 u h1 v = h2 u ... hn v = g
If this functor preserves the equaliser then, since Fu([id]) = Fv([id]) we obtain p:B->A such that ep~id. Thus we have maps h1..hn with the desired properties. To show pe=id we calculate as follows: epe=h1 u e = h1 v e = h2 u e = ... = hn v e = e, so pe=id since e is a mono.
Best wishes, Martin Hofmann
10-Aug-2001 20:51:12 -0300,1517;000000000000-0000000a
Bob Pare's answer fully answers the immediate question. Please allow me to add mention of a little observation on absolute colimits (not just coequalizers) in the context of enriched categories which appears as: Absolute colimits in enriched categories, Cahiers topologie et géométrie différentielle 24 (1983) 377- 379; MR85i:18001. It is a good opportunity for me to push the notion of weighted (or indexed) limit; see Francis Borceux's books (p. 327 of Book II) and G. Max Kelly's book (almost the central notion!). Absoluteness is nicely expressible in terms of the weight. --Ross
participants (4)
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Martin Hofmann -
Michael Barr -
pare@mscs.cs.dal.ca -
Ross Street