After calculating the group extensions of Z+Z by Z, with constant action, I am curious whether the groups have any more natural form than I found. I mean extension of Z+Z by Z in this sense, as a sequence of groups where E need not be commutative: 0 --> Z --> E --> Z+Z --> 0 and the kernel is in the center of E. The form I found is parametrized by the integers this way: For any integer c, the group E_c has triples of integers (i,,j,k) as elements and the multiplication rule is coordinate-wise addition plus an extra bit in the first coordinate. (i,,j,k).(q,r,s) = ( (i+j+c.(kr)), j+r, k+s) When c=0 this is commutative and is just the coproduct Z+Z+Z. In any group E_c, the element (c,0,0) is the commutator of (0,0,1) and (0,1,0). The Baer sum of extensions corresponds to addition of the parameters c as integers. So I understand the group of extensions. Of course I understood it before I calculated it, since it is the second cohomology group of the torus. That is why I tried the algebraic calculation. But is there a natural way to think about each group E_c, for non-zero values of c? Do these groups appear in any other natural way? thanks, colin
Try the Heisenberg group of upper triangular matrices with 1's on the diagonal and the integers i,j,k in the upper non diagonal entries. 1 k i 0 1 j 0 0 1 This should give the case c=1, but your formula is not quite correct as the RHS does not involve q. Should it be q + j + c.(kr)? Ronnie Brown http://www.bangor.ac.uk/~mas010 ----- Original Message ----- From: "Colin McLarty" <cxm7@po.cwru.edu> To: <categories@mta.ca> Sent: Monday, April 26, 2004 3:58 AM Subject: categories: Extensions of Z+Z by Z
After calculating the group extensions of Z+Z by Z, with constant action, I am curious whether the groups have any more natural form than I found. I mean extension of Z+Z by Z in this sense, as a sequence of groups where E need not be commutative:
0 --> Z --> E --> Z+Z --> 0
and the kernel is in the center of E.
The form I found is parametrized by the integers this way: For any integer c, the group E_c has triples of integers (i,,j,k) as elements and the multiplication rule is coordinate-wise addition plus an extra bit in the first coordinate.
(i,,j,k).(q,r,s) = ( (i+j+c.(kr)), j+r, k+s)
When c=0 this is commutative and is just the coproduct Z+Z+Z. In any group E_c, the element (c,0,0) is the commutator of (0,0,1) and (0,1,0). The Baer sum of extensions corresponds to addition of the parameters c as integers. So I understand the group of extensions. Of course I understood it before I calculated it, since it is the second cohomology group of the torus. That is why I tried the algebraic calculation.
But is there a natural way to think about each group E_c, for non-zero values of c? Do these groups appear in any other natural way?
thanks, colin
I've often come across such central extensions when studying various topics in algebra. For reasons which are obvious from the messages of Ronnie Brown and John Baez, I've been calling such extensions "Heisenberg extensions". The general construction is the following: Let A and C be abelian groups, and f:AxA ----> C be bilinear. Then f is a 2-cocycle for the trivial action of A on C, and the corresponding central extension has the form E = CxA with composition law given by the usual formula: (c,a)(c',a') = (c+c'+f(a,a'), a+a'). The classes of such extensions form a subgroup of the group of all classes of central extensions of A by C, but in general is not the whole group. If C is uniquely divisible by 2, then these extensions have the property that they split over every cyclic subgroup of A. The analogous construction for finite group schemes plays a role in certain questions in Galois theory and related matters; see, e.g., my paper, "On a variant of the Witt and Brauer groups", in "Brauer Groups (Evanston 1975)", Springer LNM 549 (pp 148-187). Also, relatively free groups for certain varieties of nilpotent groups of class 2 can be constructed as Heisenberg extensions. In particular, the integral Heisenberg group is the 2-generator relatively free group for the variety of all nilpotent groups of class 2. Steve Chase ---------------------------- Original Message ---------------------------- Subject: categories: Extensions of Z+Z by Z From: "Colin McLarty" <cxm7@po.cwru.edu> Date: Sun, April 25, 2004 10:58 pm To: categories@mta.ca -------------------------------------------------------------------------- After calculating the group extensions of Z+Z by Z, with constant action, I am curious whether the groups have any more natural form than I found. I mean extension of Z+Z by Z in this sense, as a sequence of groups where E need not be commutative: 0 --> Z --> E --> Z+Z --> 0 and the kernel is in the center of E. The form I found is parametrized by the integers this way: For any integer c, the group E_c has triples of integers (i,,j,k) as elements and the multiplication rule is coordinate-wise addition plus an extra bit in the first coordinate. (i,,j,k).(q,r,s) = ( (i+j+c.(kr)), j+r, k+s) When c=0 this is commutative and is just the coproduct Z+Z+Z. In any group E_c, the element (c,0,0) is the commutator of (0,0,1) and (0,1,0). The Baer sum of extensions corresponds to addition of the parameters c as integers. So I understand the group of extensions. Of course I understood it before I calculated it, since it is the second cohomology group of the torus. That is why I tried the algebraic calculation. But is there a natural way to think about each group E_c, for non-zero values of c? Do these groups appear in any other natural way? thanks, colin
participants (3)
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Colin McLarty -
Ronald Brown -
Stephen Urban Chase